calculus - $lim_{xrightarrow 0^+} frac {ln(x)}{ln( sin x)}$ without l'Hôpital's rule

How to calculate $\displaystyle
\lim_{x\rightarrow 0^{+}}\frac{\ln x}{\ln (\sin x)}$ without l'Hôpital's rule please?
If anybody knows please help
I don´t have any idea :-(
I´m looking forward your helps