Simplify $\sin(4x)\cos(4x)$ using double angle or compound trigonometry.
Can someone please show me how its done, Ive tried several times but no where near the answer.
Answer
The double angle formula is $ \ 2 \sin\theta\cos\theta = \sin(2\theta) \iff \sin\theta\cos\theta = \frac{1}{2} \sin(2\theta)$.
By applying this formula with $\theta = 2x$, we obtain
$$\sin4x\cos4x=\frac{1}{2} \sin(8x).$$
No comments:
Post a Comment