Friday, 26 June 2015

linear algebra - Show that the matrix $(c{bf A})^n= c^n{bf A}^n$

I am being asked to show that given a square, invertible matrix $\bf A$, then $(c{\bf A})^n= c^n{\bf A}^n$ for all non zero $c$'s in $\mathbb R$.



I've tried just sort of writing down the definition of invertibility and playing a bit with that but it doesn't seem to be working. I think perhaps there's some basic property I'm missing.




Thanks for any help.

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