I have proof that $0^n$ = undefined.
Since,
$2^5 = 32$,
$2^4 = 16$,
$2^5/2 = 32/2 = 16 = 2^4$.
Similarly if $0^n = 0$.
Then,
$0^{n-1} = 0$
$0^0/0 = 0/0 = 0^{n-1}$.
But $0/0$ is undefined.
Therefore $0^n = 0$.
But calculators give the result of $0^n$ as $0$. Can you explain where I am going wrong.
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