real analysis - Sum of $ 1+frac{1}{4}+frac{1}{9}+frac{1}{16}+.....$

I know that the series b. converges as $\sum \frac{1}{n^p}$ converges for $p>1$, So a. also converges. I want to know the sum.

a.$1+\frac{1}{9}+\frac{1}{25}+\frac{1}{49}+.....$

$b.1+\frac{1}{4}+\frac{1}{9}+\frac{1}{16}+.....$