calculus - Find the limit of $(2sin x-sin 2x)/(x-sin x)$ as $xto 0$ without L'Hôpital's rule

I wonder how to do this in different way from L'Hôpital's rule:

$$\lim_{x\to 0}\frac{2\sin x-\sin 2x}{x-\sin x}.$$

Please help me solve this without using L'Hopital's rule.