trigonometry - Evaluate this trig limit without L'Hospital: $lim_{xto 0};xtanleft(frac{pileft(1-xright)}{2}right)$

$$\lim_{x\to\ 0}\;x \tan\left(\dfrac{{\pi}\left(1-x\right)}{2}\right)$$

How do you do this without L'Hospital's Rule?

The result is supposed to be $\dfrac{2}{{\pi}}$.