Thursday, 2 January 2020

trigonometry - How to simplify y=sin(fracarcsin(x)n),n1?




y=sin(arcsin(x)n),n1



I know that:



limx0xy=n



But I can't figure out what the curve of x/y practically represents. Is there an obvious simple solution?


Answer



Let θ=arcsinx and we have to assume that |x|<12.




Then tanθ=x1x2 and |tanθ|<1.



cosθn+isinθn=(cosθ+isinθ)1n=(cosθ)1n(1+itanθ)1n=x1n(1+ix1x2)1n=x1nk=0(1/nk)ik(x1x2)kcosθn=x1nk=0(1)k(1/n2k)(x21x2)ksinθn=x1nx1x2k=0(1)k(1/n2k+1)(x21x2)k



NOTES







We define (zn) where zR and 0nZ as follows



(z)n={1If n=0.z(z1)(z2)(zn+1)If n1.




then (zn)=(z)nn!



It can be shown that, if |x|<1, then (1+x)z=k=0(zk)xk


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