I am wondering whether we have for f(x):=∞∑k=0|x|2k(k!)2
that
limx→∞eε|x|εf(x)=∞
for any ε>0?
I assume that this is true as factorials should somehow outgrow powers, but I do not see how to show this rigorously?
Does anybody have an idea?
I am wondering whether we have for f(x):=∞∑k=0|x|2k(k!)2
limx→∞eε|x|εf(x)=∞
I assume that this is true as factorials should somehow outgrow powers, but I do not see how to show this rigorously?
Does anybody have an idea?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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