I`m trying to show that this integral is converges and <2
∫∞0(sin(x)x)2dx<2
What I did is to show this expression:
∫10(sin(x)x)2dx+∫∞1(sin(x)x)2dx
Second expression :
∫∞1(sin(x)x)2dx<∫∞1(1x2)2dx=limb→0−1x|b0=1
Now for the first expression I need to find any explanation why its <1 and I will prove it.
I would like to get some advice for the first expression. thanks!
Answer
Hint: limx→0sinxx=1.
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