Monday, 19 November 2018

sequences and series - Prove that xmapstosuminftyn=0fn(x)=suminftyn=0fracx2(1+x2)n does not converge uniformly on [1,1]



For each n, we define fn:RR


xfn(x)=x2(1+x2)n

We consider the function
f:RR


xf(x)=n=0fn(x)=n=0x2(1+x2)n



I want to show that the series does not converge uniformly on [1,1] but I'm finding it difficult to do that.



First of all, I considered the Weierstrass M test.



MY TRIAL



|fn(x)|=|x2(1+x2)n|1(1+x2)n,x[1,1],nN




I'm also thinking that the βn=supx[1,1]|ni=0fi(x)i=0fi(x)| approach could be very helpful too!


Answer



The convergence is not uniform.



For x0 this is a geometric series:



n=0x2(1+x2)n=x21111+x2=x2+1



and for x=0 the sum is 0.




Therefore



f(x)={x2+1, if x00, if x=0



Since f is not continuous, the convergence cannot be uniform.


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