Suppose that F is a σ-algebra on a set X and μ:F→[0,∞] satisfies the conditions:
- μ(∅)=0.
- For every pair A and B of disjoint sets in F, μ(A∪B)=μ(A)+μ(B).
- For every decreasing sequence {En} in F (that is En+1⊆En for all n) such that ⋂∞n=1En=∅, we have limn→∞μ(En)=0.
Prove that μ is a measure on F.
Here's my attempt:
Proof.
Let {En} be a countably infinite collection of sets such that Ei∩Ej=∅ for all i,j. Write
E=∞⋃n=1En
and let
Fn=E∖n⋃k=1Ek.
for n≥1.
Then we have
Fn+1=E∖n+1⋃k=1Ek⊆E∖n⋃k=1Ek=Fn
and
∞⋂n=1Fn=∅.
Hence, by applying condition (2), we have
μ(Fn)=μ(E∖n⋃k=1Ek)=μ(E)−μ(n⋃k=1Ek)=μ(E)−n∑k=1Ek
and the above holds for all n∈N. Thus, applying condition (3), we have
μ(E)=limn→∞μ(Fn)+limn→∞n∑k=1Ek=∞∑k=1Ek.
This shows that μ is a measure.
Answer
Your proof is correct.
There are some minor typos in some places, where you wrote Ek instead of μ(Ek), but I am sure you meant the right thing.
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