If the 3rd , 5th and 8th terms of an arithmetic progression with a common difference of 3 are
three consecutive terms of a geometric progression , then what is common ratio? Help me with step-by-step.
Regards!
Answer
a+2da=a+5da+2d⟹a2+4ad+4d2=a2+5ad⟹4d2=ad
Thus, a=4d or d=0. Since we are given d=3, we must have a=12. Thus, the common ratio is
a+2da=a+5da+2d=32
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