Solutions of following eqution
x=√2+√2−√2+√2−x
is 1+√52.
This is solution of
x=√2+√2−x
Does all of this type equation(repeating same shape) always have same solutions like this?
Can you explain why?
Answer
Note the following identities: 2+2sin(θ)=4sin2(θ/2+π/4)
Consider x=√2+√2−√2+√2−x
where x=2sin(θ).
Using the above identities, it must be that
2sin(θ)=√2+√2−√2+2sin(π/4−θ/2)
2sin(θ)=√2+√2−2sin(3π/8−θ/4)
2sin(θ)=√2+2sin(θ/8+π/16)
sin(θ)=sin(θ/16+9π/32)
θ=3π/10
Note that 2sin(3π10)=1+√52.
I would conjecture that, yes, equations in that general form will have a solution in the form of the sine or cosine of some rational multiple of π.
It is worth noting that sin(pqπ) will be algebraic per this thread.
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