Saturday, 26 May 2018

calculus - continued square root function



Solutions of following eqution
x=2+22+2x


is 1+52.
This is solution of
x=2+2x




Does all of this type equation(repeating same shape) always have same solutions like this?
Can you explain why?


Answer



Note the following identities: 2+2sin(θ)=4sin2(θ/2+π/4)

22sin(θ)=4sin2(π/4θ/2)



Consider x=2+22+2x



where x=2sin(θ).



Using the above identities, it must be that




2sin(θ)=2+22+2sin(π/4θ/2)



2sin(θ)=2+22sin(3π/8θ/4)



2sin(θ)=2+2sin(θ/8+π/16)



sin(θ)=sin(θ/16+9π/32)



θ=3π/10




Note that 2sin(3π10)=1+52.



I would conjecture that, yes, equations in that general form will have a solution in the form of the sine or cosine of some rational multiple of π.



It is worth noting that sin(pqπ) will be algebraic per this thread.


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