My Maple input limit(sin(1/n)*n,n=infinity);
says 1.
I don't understand why
limn→∞sin(1n)⋅n=1
I know that limn→∞1/n=0, so it kind of says "0 * infinity = 1".
Have I overlooked some rewriting of sin(1/n)n?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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