I'm having trouble showing that:
cos(3π8)=1√4+2√2
The previous parts of the question required me to find the modulus and argument of z+i where z=cisθ. Hence, I found the modulus to be 2cos(π4−θ2) units and that the argument would be arg(z+i)=π4+θ2.
Now, the next step that I took was that I replaced every theta with 3π8 in the polar form of the complex number z+i. So now it would look like this:
z+i=[2cos(π8)]cis(3π8)
Then, I expanded the cis(3π8) part to become cos(3π8)+isin(3π8). So now I've got the cos(3π8) part but I don't really know what to do next. I've tried to split the angle up so that there would be two angles so I can use an identity, however, it would end up with a difficult fraction instead. So if the rest of the answer or a hint would be given to finish the question, that would be great!!
Thanks!!
Answer
As 3π8 and π8 are complementary angles, we get
cos3π8=sinπ8=sinπ/42=√1−cos(π/4)2=√1−(1/√2)2=√√2−12√2=√√2−12√2⋅√2+1√2+1=√14+2√2=1√4+2√2
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