Is d1∣n,d2∣n⟺[d1,d2]∣n
true ? And if yes, how can I prove it ? I recall that [d1,d2] is the least common multiple.
My tries
For the implication : Let d1∣n and d2∣n. Then, d1d2∣n2. By the way, since d1,d2∣n, we have that (d1,d2)∣n where (d1,d2)=:gcd(d1,d2) and thus [d1,d2](d1,d2)∣n2.
Question: How can I get [d1,d2]∣n from this?
For the converse, since d1,d2∣[d1,d2]∣n, the claim follow.
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