Find the remainder when 528528528...up to 528 digits is divided by 27?
Here's what I have done: The number can be written as 528⋅10525+528⋅10522+...+528 which has 176 terms and each term is ≡15mod27 thus the number should be 176∗15mod27 hence 21 should be the remainder. But book says it is 6. I don't understand the flaw in my logic. Please correct me.
Answer
Here is a python3 session
>>> s = '528' * 176
>>> len(s)
528
>>> int(s) % 27
21
Isn’t that addition of all the digits methodology applicable for divisibility by 3 and 9, I am not sure if you can apply the same to 27?
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