I have a complex number $8-6 i$ . I have to find the square root . I did all the steps and I got $\pm(-3+i)$. I also got $\pm(3-i)$. On squaring I am getting the same $8-6 i$, but what is the right square root . Please someone point out my mistake.
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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