I have a complex number 8−6i . I have to find the square root . I did all the steps and I got ±(−3+i). I also got ±(3−i). On squaring I am getting the same 8−6i, but what is the right square root . Please someone point out my mistake.
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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