∞∑n=1cos(nπ)sin(π√n)
I know that to show that a series is conditionally convergent, I will have to show that the series is convergent, and also show that the absolute value of the series is divergent.
I am able to show that ∞∑n=1cos(nπ)sin(π√n) is convergent using the alternating series test, where the limit is equals to 0 and the expression is non-increasing. But I have no idea how to show that the absolute value of the series is divergent. Please correct me if my concept is wrong.
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