algebra precalculus - Evaluate this continued trigonometric sum

$$\sin^2(4) + \sin^2(8) + \sin^2(12) + ... + \sin^2(176)$$

Where the number is in degrees not radians.

$$\cos(x) = \sin(90 - x) \implies \cos(x) = \sin(90 + x)$$

$$\implies \sin(x) = \cos(x - 90)$$

$$S = \sum_{n=1}^{44} \sin^2(4n)$$