I want to find the value of lim
I have already tried using L'Hôpital's rule, only to find a seemingly more daunting limit.
Answer
Let P_n = (1+1/n)^n. Then
\log{P_n} = n \log{\left ( 1+\frac1{n} \right )} = n \left (\frac1{n} - \frac1{2 n^2} + \cdots \right) = 1-\frac1{2 n} + \cdots
P_n = e^{1-1/(2 n)+\cdots} = e \left (1-\frac1{2 n} + \cdots \right )
Thus
\lim_{n \to \infty} n (e-P_n) = \frac{e}{2}
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