How do I show that the following function is differentiable at $(0,0)$?
$$
\begin{cases}
\dfrac{\sin(xy)}{y}, & \text{if }y \neq 0 \\
\\
0, & \text{if }y = 0
\end{cases}
$$
I calculated the partial derivatives and
- $f(x) = \cos(xy)$ exists near $(0,0)$ and is continuous
- $f(y) = \dfrac{xy \cos(xy) - \sin(xy)}{y^2}$ exists, but how do I show that it is continuous?
No comments:
Post a Comment