Thursday, 26 December 2013

multivariable calculus - Show that $frac{sin(xy)}{y}$ is differentiable at $(0,0)$.

How do I show that the following function is differentiable at $(0,0)$?
$$
\begin{cases}
\dfrac{\sin(xy)}{y}, & \text{if }y \neq 0 \\
\\
0, & \text{if }y = 0
\end{cases}
$$
I calculated the partial derivatives and





  • $f(x) = \cos(xy)$ exists near $(0,0)$ and is continuous

  • $f(y) = \dfrac{xy \cos(xy) - \sin(xy)}{y^2}$ exists, but how do I show that it is continuous?

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real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...