How would one go about obtaining a closed form for the n-th derivative of sin(x)x I took a few of the derivatives but didn't see any immediate pattern.
There may be some obvious thing I'm missing, or overthinking it.
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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