To complete a certain work, a workman $A$ alone would take $m$ times as many days as $B$ and
$C$ working together; $B$ alone would take n times as many days as $A$ and $C$ together; $C$ alone
would take $p$ times as many days as $A$ and $B$ together : show that the numbers of days in
which each would do it alone are as $m + 1 : n + 1 : p + 1$
I just need hint as how to approach this problem as I am not able to initiate. Please provide some guidance
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