Thursday, 23 October 2014

calculus - Function whose integral over $[0, infty)$ is finite, but the limit of the function is $>0$

Let $t \in \mathbb{R},f:\mathbb{R} \rightarrow \mathbb{R}:t \mapsto f(t)$.




$f$ is required to have:




  1. $\displaystyle\lim_{t \rightarrow \infty} f(t) = L$, where $L>0$ (could be $\infty$, so the limit exists, only it could be $\infty$)


  2. $\displaystyle\int_{0}^{\infty} f(t) dt < \infty$




Is that possible to construct such $f$?



Note:




$f$ can be any function continuous or discontinuous.



I found the discussion here which is involving "tent" function but in that example, the limit does not exist.



Note 2: I have edited the title. Thank you for your fedback !!!



Thank you for any answers or comments.

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...