Sunday 12 October 2014

Proof by contradiction$,-,$functional equation

Show that there does not exist a strictly increasing function $f : N → N $ satisfying $f (2) = 3$ and $f (mn) = f (m)f (n)$ for all $m, n ∈ N$.



My Attempt



It can be found that $f(2^x)=3^x$ from which we can conclude that $f(x)=3^{\log_2 x}$ and by which we can argue that for all natural $x$, $f(x)$ is not always natural, so contradiction hence such a function doesn't exist.
Is this proof correct? If not what should be changed?

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...