discrete mathematics - Prove $(1+2+...+k)^2 = 1^3 + ... + k^3$ using induction

I need to prove that

$$(1+2+{...}+k)^2 = 1^3 + {...} + k^3$$
using induction.
So the base case holds for $0$ because $0 = 0$ (and also for $1$: $1^2 = 1^3 = 1$)
I can't prove it for $k+1$ no matter what I try! Can you give me a hint?