Thursday, 25 February 2016

radicals - Prove that the square root of 3 is irrational

I'm trying to do this proof by contradiction. I know I have to use a lemma to establish that if x is divisible by 3, then x2 is divisible by 3. The lemma is the easy part. Any thoughts? How should I extend the proof for this to the square root of 6?

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real analysis - How to find limhrightarrow0fracsin(ha)h

How to find limh0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...