Wednesday, 9 January 2013

algebra precalculus - Find the sum of the series suminftyn=1frac1(n+1)(n+2)(n+3)cdots(n+k)

Find the sum of the series



n=11(n+1)(n+2)(n+3)(n+k)



Given series




n=11(n+1)(n+2)(n+3)(n+k)



=1234(k+1)+1345(k+2)+1456(k+3)+



now how to proceed further in this pleas suggest thanks ....

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