Tuesday, 9 February 2016

analysis - Property of Laplace transforms

I was looking at this answer to the question asked and I am curious about the




$$\int_0^\infty F(u)g(u) du = \int_0^\infty f(u)G(u) du $$



relationship being used. I referred to the link provided in the answer, but it discussed the Mellin transform, not the Laplace transform, and I am not making the connection.



I was wondering if someone could explain where this relationship comes from or where I could learn more about it, and if it is true for laplace transforms in general, or only for that specific problem.

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...