Wednesday, 6 September 2017

calculus - Compute limntoinftyfrac1nln(3fracn1+3fracn2+cdots+3fracnn)



limn1nln(3n1+3n2++3nn)


I tried to apply the squeeze theorem, but I can't manage to solve it.


Answer



The squeeze theorem is a good idea. ln(3n)ln(3n1+3n2++3nn)ln(n3n)


No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find limh0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...