calculus - Find the limit as $x$ approaches $5$

$f(x) = \dfrac{\sin(x-5)}{x^2-2x-15}$

Find the limit as $x$ approaches $5$.

I got up to : $\dfrac{\sin}{ ( x+3)}$.

I know the answer is $\frac18$ but I just don't know how to get it.

Unfortunately, I did cancel out the (x-5) =(. Is it because the the numerator (x-5) is considered an angle? like sin theta? and is not similar to the one in the denominator?