I need to show that the series ∞∑n=3(log(log(n))2n(log(n))2
converges.
I'm trying to find some upper bound for it, since the tests i've used so far did not lead to any useful conclusion. I think that a good upper bound might be the series ∑∞n=31n(log(n))1+ϵ, for ϵ>0 because then i could use the fact that the series ∑∞n=31n1+ϵ converges. Therefore i tried to approximate the expression (loglogn)2 to something like
(loglogn)2≤(logn)1+δ
for some δ>0 but without success. Could you please help me?
Answer
Hint: for n big enough,
(loglogn)2<√logn
Now use the fact that ∑1n(logn)3/2<∞
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