Evaluate $\lim\limits_{n\to\infty}n\int\limits_0^1 f(x)e^{-nx}\mathrm dx$ where $\,f$ is bounded in $\mathbb{R}^+\cup\{0\}$.
My problem is that I think there's missing information about $f$, e.g. some kind of continuity on $0$. Because if we change the variable of integration for $\frac xn$ the integral is equal to
$$\lim\limits_{n\to\infty}\int\limits_0^n f\left(\frac xn\right)e^{-x}\mathrm dx$$
And that can be dominated by $Me^{-x}$, where $|f|\leq M$. But the convergence is to a function non continue (necessary).
Am I wrong?
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