Wednesday, 13 December 2017

summation - Limit of triple sum

Suppose one has the following triple sum:



Sn=ns=0st=0su=0f(n,t)g(n,u)




where for all n, α<Sn<α for some real constant α<. Since Sn is bounded above and below by a constant may one interchange the limit with the first summand, obtaining
lim



Since the limit is now inside the first summand, may one now consider s as a constant and thus bring the limit inside the two other summands to the right of it, yielding



\lim_{n\to\infty}S_n=\sum_{s=0}^{\infty}\sum_{t=0}^s\sum_{u=0}^s\left(\lim_{n\to\infty}f(n,t)g(n,u)\right)?



If not, why not?

No comments:

Post a Comment

real analysis - How to find lim_{hrightarrow 0}frac{sin(ha)}{h}

How to find \lim_{h\rightarrow 0}\frac{\sin(ha)}{h} without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...