Tuesday, 20 March 2018

real analysis - Dense subset of continuous functions



Let C([0,1],R) denote the space of real continuous functions at [0,1], with the uniform norm. Is the set H={h:[0,1]R:h(x)=nj=1ajebjx,aj,bjR,nN} dense in C([0,1],R)?


Answer



Yes, by the general Stone-Weierstrass Approximation Theorem. Indeed, H is an algebra of continuous real-valued functions on the compact Hausdorff space [0,1], and H separates points and contains a non-zero constant function. That is all we need to conclude that H is dense in C([0,1],R).


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