This claim is false $\sum_{n=1}^{\infty}n=\sum_{n=1}^{\infty}n^{-(-1)}= \zeta(-1)=-1/12$.
The error is that we should
$\sum_{n=1}^{\infty}n=\sum_{n=1}^{\infty}(1/n ^1)^{-1}=(0)^{-1}$.
Am I correct? It's difficult to say that an infinite sum like that don't diverge and that sum of positive numbers can give negative number.
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