This claim is false ∑∞n=1n=∑∞n=1n−(−1)=ζ(−1)=−1/12.
The error is that we should
∑∞n=1n=∑∞n=1(1/n1)−1=(0)−1.
Am I correct? It's difficult to say that an infinite sum like that don't diverge and that sum of positive numbers can give negative number.
This claim is false ∑∞n=1n=∑∞n=1n−(−1)=ζ(−1)=−1/12.
The error is that we should
∑∞n=1n=∑∞n=1(1/n1)−1=(0)−1.
Am I correct? It's difficult to say that an infinite sum like that don't diverge and that sum of positive numbers can give negative number.
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
No comments:
Post a Comment