Construct a function which is continuous in $[1,5]$ but not differentiable at $2, 3, 4$.
This question is just after the definition of differentiation and the theorem that if $f$ is finitely derivable at $c$, then $f$ is also continuous at $c$. Please help, my textbook does not have the answer.
Answer
$|x|$ is continuous, and differentiable everywhere except at 0. Can you see why?
From this we can build up the functions you need: $|x-2| + |x-3| + |x-4|$ is continuous (why?) and differentiable everywhere except at 2, 3, and 4.
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