How can one evaluate the following integral?
∫c−ce−ax2cos2(bx)dx
Wolfram Alpha gives this. Is there not a more compact form?
If ∫c−ce−ax2dx=k, then can we express the first integral in terms of k? Thanks.
How can one evaluate the following integral?
∫c−ce−ax2cos2(bx)dx
Wolfram Alpha gives this. Is there not a more compact form?
If ∫c−ce−ax2dx=k, then can we express the first integral in terms of k? Thanks.
How to find lim without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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