Tuesday, 12 February 2013

combinatorics - Number of solutions of x1+2x2+3x3+cdots+nxn=p


Given a non-negative integer p. What is the number of solutions of x1+2x2+3x3++nxn=p, where the xi's are non-negative integers.




Can we answer this by using number of solutions of x1+x2+x3++xm=q for any m,q?

No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find lim without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...