Tuesday, 12 February 2013

combinatorics - Number of solutions of x1+2x2+3x3+cdots+nxn=p


Given a non-negative integer p. What is the number of solutions of x1+2x2+3x3+⋯+nxn=p, where the xi's are non-negative integers.




Can we answer this by using number of solutions of x1+x2+x3+⋯+xm=q for any m,q?

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