Find the sum of this series:
$\sum_{r=1}^{19}\left( (-1)^{r-1}\frac{r}{{20\choose r}}\right)$
NOTE: ${20\choose r}$ = $\frac{20!}{(20-r)!r!}$
The final answer is 10/11.
I do have a way to solve this, but i find that to be wayy too tedious and long. Please don't use concepts that are above high school level.
Thanks in advance!
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