Let f(x) be a continuous function in [0,1] so that for every x∈[0,1] there is f(x)∈[0,1].
Prove that there such a point x0∈[0,1] so that x0+f(x0)=1
Could you please point me to the right direction with this question?
I Tried proving it using Stone–Weierstrass theorem and intermediate value theorem but didn't got anywhere.
Thanks!
Answer
The function g(x):=x+f(x) is continuous on [0,1] and has g(0)=f(0)≤1 and g(1)=1+f(1)≥1. Hence, by the intermediate value theorem, g(x0)=1 for some x0∈[0,1], i.e., x0+f(x0)=1 for some x0∈[0,1].
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