Let Ω⊂R2 be bounded and closed, and let g:Ω→[0,∞) be continuous. Let g(x0,y0)=max. Show that:
\exists \rho_{x_0},\rho_{y_0}>0, \forall(x,y)\in \Omega,|x-x_0|<\rho_{x_0},|y-y_0|<\rho_{y_0}, then g(x,y_0)\geq g(x,y).
In fact, I think the \Omega is bounded and closed is not necessary. All of the above is my guess, I really don't know whether it is right. Thanks for any answer or advice.
Answer
It is not true. The strict inequality is trivially false by taking x=x_0, y=y_0. The non-strict one is not true either. Consider g(x,y)=-(x-y)^2 and (x_0,y_0)=(0,0). Then
$$
g(x,y_0)=-x^2
for all x\ne x_0.
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