Prove the following:
11+k=1k1+1k≤ln(1+1k)≤1k
I know I can prove it with induction if the values were naturals. However, the "problem" for me is that they're real.
Answer
For all x∈R,
ex≥1+x
Taking log on both sides we get,
ln(1+x)≤x,∀x>−1
Substituting x=1k,k∉[0,−1], we get,
ln(1+1k)≤1k
Substituting x=−1k+1,k∉[0,−1], we get,
ln(kk+1)≤−1k+1⇒ln(1+1k)≥1k+1
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