I need to evaluate this integral ∫100x2e−x22dx
but I'm not sure how. The problem also states that ∫∞0x2e−x2βdx=β1+1βΓ(1α)α2
but I don't know what that means. Can somebody point me in the right direction ?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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