By using the complex representations of sine and cosine, show that n∑m=0sinmθ=sinn2θsinn+12θsin12θ
So I am not too sure how to go about this proof. I tried to substitute sine for its complex representation but I can't see how to evaluate the sum?
How to find lim without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
No comments:
Post a Comment