I tried to do a change of variable with $t=\frac{1}{n}$ in order to use Taylor expansion but the factor $n!$ becomes a fractional number (during the lesson it was define only for $\mathbb{Z}$ set number).
Another attempt I made was to write the limit as $\lim_{n \to \infty} \sqrt[n]{\frac{n!}{n^n}} \rightarrow e^{\frac{1}{n}log{\frac{n!}{n^n}}}$ but it doesn't work. After that I tried to use the Stirling formula and yes... it works! But I would find something that doesn't use this formula.
Some advice?
Thursday, 9 May 2013
calculus - $lim_{n to infty} frac{sqrt[n]{n!}}{n}$
Subscribe to:
Post Comments (Atom)
real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
-
$$ 3x+6y+5z=7 $$ The general solution to this linear Diophantine equation is as described here (Page 7-8) is: $$ x = 5k+2l+14 $$ $$ y = -l $...
-
How to show the following inequality in Measure Theory: If $f$ is a non-negative measurable function defined on a measurable set $E$ then ...
-
I need help to compute the following integral: $$\int_{-\infty}^{\infty}\frac{z^4}{1+z^8}dz$$ I need to use Cauchy's residue theorem. I ...
No comments:
Post a Comment