Given a1=1 and an=an−1+4 where n≥2 calculate,
limn→∞1a1a2+1a2a3+⋯+1anan−1
First I calculated few terms a1=1, a2=5, a3=9,a4=13 etc. So
limn→∞1a1a2+1a2a3+⋯+1anan−1=limn→∞15+15×9+⋯+1anan−1
Now I got stuck. How to proceed further? Should I calculate the sum ? Please help.
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