Saturday, 27 September 2014

limits - Calculate limlimitsxto0+efrac1x2sinx

I want to investigate the value of limx0+e1x2sinx. Since the expontial tends really fast to infinity but the sine quite slowly to 0 in comparison I believe the limit to be infinity. But I cannot find I way to prove it. I tried rewriting using the standard limit sinxx as sinxxxe1x2 but I still get an indeterminate form "10".

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real analysis - How to find limhrightarrow0fracsin(ha)h

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